Reuse of resource variables...

php.internals

Frank M. Kromann

22 years ago
Hi, When I do $rs = fbsql_query(...); /* more code here */ $rs = fbsql_query(...); The second query does not return anything. If I use another variable name for the second result or if I do $rs = fbsql_query(...); /* more code here */ $rs = 0; $rs = fbsql_query(...); everything works fine. I have checked that the list descructor gets called in both cases. What am I missing here ? - Frank